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In order to read or download Die kwart voor sewe Lelie Book Mediafile Free File Sharing ebook, you need to create a FREEÂ . For optimal results, you need to disable your ad blocker for this site. The selected file has a size of Kwart Voor Sewe Lelie Free Downloads and is located in the database.Q: Show that all $n-1$ of the elements of $\{1,2,3,….n\}$ can be made even by adding either 0,1 or 2 to each member. Show that all $n-1$ of the elements of $\{1,2,3,….n\}$ can be made even by adding either 0,1 or 2 to each member. I know that the previous question is answered here. The problem I have is that this question seems too simple in comparison to the solution given. It seems as though the’solution’ is not even a solution. I want to know how to find the solution to this question. What changes do I need to make in the solution to the previous question. A: You can do it by induction on $n$: For $n = 1$ the statement is trivial, since we have to add $1,2,3$ to get a number that’s even. Now assume the statement is true for $n$ and apply it to $n+1$: Let $n+1=2m$. The sum of the elements is $k=(m+1)^2 = (n+1)+2\cdot (m-1)$ and the sum of the even numbers is $k-2 = (m-1)^2$. Since $k$ is even $k-2$ has to be even, which implies $m-1$ is even as well. Now let $n+1=2m+1$. Again we can look at the sum of the numbers and the sum of the even numbers: $$k = (m+2)^2 = (n+1)+2\cdot (m+1)-2 = (n+1)+2\cdot (m-1) + 4$$ Since $k$ is even, so must $4$ be. But the sum of the even numbers is even, so we can conclude that $m+1$